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Finite Variance = Autocorrelation symmetric + positive semidefinite

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Theorem
LinearAlgebraProbabilityInfoTheory

Theorem

Let X=(X1,…,Xk)T\mathbf{X}=(X_{1},\dots,X_{k})^{T} be a random vector having finite variance. Then the kƗkk\times k autocorrelation matrix RX={E[XiXj]}\mathbf{R_{X}}=\{ E[X_{i}X_{j}] \} is symmetric and positive semidefinite.