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Theorem (Binomial theorem)
Let x,y∈Fx,y\in\mathbb{F}x,y∈F then (x+y)n=∑k=0n(nk)xn−kyk=∑k=0n(nk)xkyn−k(x+y)^{n}=\sum\limits_{k=0}^{n} {n\choose k} x^{n-k}y^{k}=\sum\limits_{k=0}^{n}{n\choose k}x^{k}y^{n-k}(x+y)n=k=0∑n(kn)xn−kyk=k=0∑n(kn)xkyn−k