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For a multiplicative function fff, we have ∑d∣nf(d)=∏pa∥n(∑j=0af(pa))\sum_{d|n}f(d)=\prod_{p^{a}\|n}\left( \sum_{j=0}^{a} f(p^{a})\right)d∣n∑f(d)=pa∥n∏(j=0∑af(pa))where pa∥n ⟺ pa∣n & pa+1∤np^{a}\|n\iff p^{a}|n \ \& \ p^{a}+1\not\mid npa∥n⟺pa∣n & pa+1∣n