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For a prime pā”1(mod4)p\equiv1\pmod{4}pā”1(mod4) we have [(pā12)!]2ā”ā1(modp)\left[ \left( \frac{p-1}{2} \right)! \right]^{2}\equiv-1\pmod{p}[(2pā1ā)!]2ā”ā1(modp) giving an explicit solution to the congruence x2ā”ā1(modp)x^{2}\equiv-1\pmod{p}x2ā”ā1(modp).