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Let K⊂RK\subset\mathbb{R}K⊂R (interval) and let f:K→Rnf:K\to\mathbb{R}^nf:K→Rn be convex function. Also let XXX be a random vector with alphabet Xn⊂K\mathcal{X}^n\subset KXn⊂K and finite component means, then E[f(X)]≥f(E[X])E[f(X)]\ge f(E[X])E[f(X)]≥f(E[X]) Also, if fff is strictly convex then the inequality is strict unless XXX is deterministic.