Created by Knut M. Synstadfrom the Noun Project

Foster-Lyapunov Theorems

Theorem (Foster-Lyapunov for Positive Harris Recurrence)

Let SS be a petite set, b∈Rb\in\mathbb{R}, ϵ>0\epsilon>0,and V:X→R+V:\mathbb{X}\to \mathbb{R}^{+}, Let {Xk}k∈N\{ X_{k} \}_{k\in\mathbb{N}} be a μ-irreducible MC. If the following is satisfied ∀x∈X\forall x\in\mathbb{X} E[V(xk+1)∣xk=x]≤V(x)−ϵ+b1{x∈S}E[V(x_{k+1})|x_{k}=x]\le V(x)-\epsilon+b\mathbb{1}_{\{ x\in S \}} then {Xk}k∈N\{ X_{k} \}_{k\in\mathbb{N}} is Positive Harris Recurrent (equivalently ∃\exists an Invariant probability measure π\pi).

Theorem (Foster-Lyapunov for Finite Expectation)

Let SS be a petite set, b∈R+b\in\mathbb{R}^{+}, and V:X→R+V:\mathbb{X}\to \mathbb{R}^{+}, f:X→[0,∞)f:\mathbb{X}\to[0,\infty) for some ϵ>0\epsilon>0. Let {xk}k∈N\{ x_{k} \}_{k\in\mathbb{N}} be a Markov chain. If the following holds E[V(xk+1)∣xk=x]≤V(x)−ϵ+b,    x∈XE[V(x_{k+1})|x_{k}=x]\le V(x)-\epsilon+b, \ \ \ \ x\in\mathbb{X}then for any Invariant probability measure π\pi we have finite expectation ∫f(x) π(dx)≤b\int\limits f(x) \, \pi(dx)\le b

Theorem (Foster-Lyapunov for Harris Recurrence)

Let SS be a compact set, b<∞b<\infty, and V:X→R+V:\mathbb{X}\to \mathbb{R}^{+} s.t. ∀α∈R+, {x:V(x)≤α}\forall\alpha\in\mathbb{R}^{+}, \ \{ x:V(x)\le \alpha \} is compact or equivalently lim⁡∥x∥→∞V(x)=∞\lim_{ \|x\| \to \infty } V(x)=\inftyLet {xk}k∈N\{ x_{k} \}_{k\in\mathbb{N}} be a Markov chain. Furthermore, let τS=min⁡{t>0:xt∈S}\tau_{S}=\min\{ t>0: x_{t}\in S \}, τBN={t>0:xt∈BN}\tau_{B_{N}}=\{ t>0:x_{t}\in B_{N} \} where BN={z:V(z)≥N}B_{N}=\{ z:V(z)\ge N \}, if we have that Px(min⁡(τS,τBN)<∞)=1P_{x}(\min(\tau_{S},\tau_{B_{N}})<\infty)=1then ∀x∈X,  E[V(xk+1)∣xk=x]≤V(x)+b1{x∈S}  ⟹  P(τS<∞)=1\forall x\in\mathbb{X}, \ \ E[V(x_{k+1})|x_{k}=x]\le V(x)+b\mathbb{1}_{\{ x\in S \}}\implies P(\tau_{S}<\infty)=1