NAVIGATION
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Let a,b∈Za,b\in\mathbb{Z}a,b∈Z, we say aaa is congruent to bbb modulo mmm if m∣a−bm|a-bm∣a−b or a=b+kma=b+kma=b+km for some k∈Zk\in\mathbb{Z}k∈Z. We represent this relationship using the following notation a≡b (mod m)a\equiv b \ (\text{mod } m)a≡b (mod m)
Chinese Remainder Theorem
Generalized Chinese Remainder Theorem
Solution to Congruence