In this system we Set Un to be an arbitrary RV with a finite second moment (i.e. E[Un2]<∞). Since en=Xn−Un and e^n=X^n−Un then we have that E[(Xn−X^n)2]=E[(Xn−Un−(X^n−Un))2]=E[(en−e^n)2]=E[(en−Q(en))2]Here we see the MSE of the reconstruction does not accumulate the error and is merely the MSE of the quantizer.