Created by Knut M. Synstadfrom the Noun Project

Invariant Distribution

Definition (Invariant distribution)

Let SS denote the state space, and P={Pij:i,jS}P=\{P_{ij}:i,j\in S\} be a transition matrix. A distribution λ={λi:iS}\lambda=\{\lambda_{i}:i\in S\} is said to be invariant with respect to PP if for any iSi\in S, λi=kSλkPki\lambda_{i}=\sum\limits_{k\in S}\lambda_{k}P_{ki}That is, λ=λP\lambda=\lambda P

Lemma (1)

If λ\lambda is an invariant measure and 0<kSλk<0<\sum\limits_{k\in S}\lambda_{k}<\infty, then λ~i=λijSλj\tilde\lambda_{i}= \frac{\lambda_{i}}{\sum\limits_{j\in S}\lambda_{j}}is an invariant distribution.

Lemma (2)

If λ\lambda is an invariant distribution and X0λX_{0}\sim\lambda, then

  1. XmλX_{m}\sim\lambda for any m1m\ge1
  2. {Xm+n:n0}\{X_{m+n}:n\ge0\} is a Markov(λ,P)Markov(\lambda,P)

Kac’s Lemma

Methods to find invariant distribution

  1. Applying the Definition: Apply the definition of an invariant distribution i.e. λ=λP\lambda=\lambda PThis always works but it could be complicated (especially if S=|S|=\infty). If S<|S|<\infty then take PT(λT)=λTP^{T}(\lambda^T)=\lambda^{T}where λT\lambda^{T} is the eigenvector corresponding to eigenvalue λ=1\lambda=1.
  2. Fix kSk\in S, then find γikEk[Tk(i)] \mboxforiS\frac{\gamma^{k}_{i}}{E_{k}[T_{k}^{(i)}]} \ \mbox{for }i\in SIf we can compute γik\gamma_{i}^{k} then it works, could be difficult though
  3. Detailed Balance

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