Itô Isometry

Motivation

Let (Xt)t≥0,(Yt)t≥0(X_{t})_{t\ge 0},(Y_{t})_{t\ge 0} be stochastic processes on (Ω,F,P)(\Omega,\mathcal{F},P). Our goal is to make sense of ∫Y dX\int\limits Y \, dX

1. Lebesgue-Stieltjes Pathwise Integral

We first tried to use the LS integral to do this. We first noted that the Lebesgue-Stieltjes measure, μg\mu_{g} only worked with gg increasing and that μg\mu_{g} was the difference between two increasing functions.

We then saw that for any g=g1−g2g=g_{1}-g_{2} where both g1,g2g_{1},g_{2} are increasing that gg then must have finite variation on R+\mathbb{R}^{+}.

We then put the final nail in the coffin by showing Continuous Martingale with finite variation is constant

To summarize, if we wished to use the LS integral to define ∫Y dX\int\limits Y \, dX we needed XX to be a continuous martingale with finite variaiton but this form meant that XX was constant which is pretty useless!

2. Riemann-Stieltjes Pathwise Integrals

We then thought, ok how about RS integrals? i.e. ∀ω∈Ωlim⁡∣π∣→0∑i=0N−1Yti(ω)(Xti+1(ω)−Xti(ω))\forall\omega\in\Omega\quad\lim_{ |\pi| \to 0 } \sum_{i=0}^{N-1}Y_{t_{i}}(\omega)(X_{t_{i+1}}(\omega)-X_{t_{i}}(\omega))where π=(t0,…,tN)\pi=(t_{0},\dots,t_{N}) is a subdivision of [0,1][0,1] (for simplicity). We then defined the following: Let g:[0,1]→Rg:[0,1]\to \mathbb{R} be continuous. Define Sπ∈C0([0,1]:R)S_{\pi}\in C^{0}([0,1]:\mathbb{R}) to be Sπ(f)=∑i=0N−1f(ti)(g(ti+1)−g(ti))S_{\pi}(f)=\sum_{i=0}^{N-1}f(t_{i})(g(t_{i+1})-g(t_{i}))Assume lim⁡∣π∣→0Sπ(f)\lim_{ |\pi| \to 0 }S_{\pi}(f) exists ∀f∈C0([0,1]:R)\forall f\in C^{0}([0,1]:\mathbb{R}). We then applied the principle of uniform boundedness to find that gg also needs to have finite variation on [0,1][0,1] in order for this to be defined i.e. ∥Sπ∥op=sup⁡∥f∥∞≤1∣Sπ(f)∣=V(g;π)\lVert S_{\pi} \rVert _{op}=\sup_{\lVert f \rVert _{\infty}\le 1}|S_{\pi}(f)|=V(g;\pi)and by the theorem we found that sup⁡n∈N∥Sπ∥op=sup⁡n∈NV(g;π)<∞\sup_{n\in\mathbb{N}}\lVert S_{\pi} \rVert _{op}=\sup_{n\in\mathbb{N}}V(g;\pi)<\infty Then considering the standard Brownian motion (Bt)t≥0(B_{t})_{t\ge 0} we computed ∫0tBs dBs=12(Bt2−t)\int\limits _{0}^{t}B_{s} \, dB_{s}=\frac{1}{2}(B_{t}^{2}-t) in probability by applying the framework of the RS integral.

Motivation Trying Again!

Let now (Mt)t≥0(M_{t})_{t\ge 0} be a right continuous L2L^{2}-martingale and (Xt)t≥0(X_{t})_{t\ge 0} be a stochastic process on (Ω,F,P)(\Omega,\mathcal{F},P). Our goal is to make sense of ∫X dM\int\limits X \, dM in a way that it agrees with the LS pathwise integrals whenever they’re defined.

Itô Isometry (0)

Now, we take gg increasing and right continuous meaning we can redefine the Lebesgue-Stieltjes measure μg\mu_{g} strictly on intervals of the type (a,b](a,b] i.e. since gg right continuous   ⟹  g(b+)=g(b)\implies g(b^{+})=g(b) and g(a+)=g(a)g(a^{+})=g(a) Hence μg((a,b])=g(b)−g(a)\mu_{g}((a,b])=g(b)-g(a) Hence for 0≤s<t0\le s<t we define ∫1(s,t]×Ω dM=Mt−Ms\int\limits \mathbb{1}_{(s,t]\times \Omega} \, dM=M_{t}-M_{s} Letting F⊂ΩF\subset\Omega we then consider 1(s,t]×F{1(s,t]ω∈F0otherwise\mathbb{1}_{(s,t]\times F}\begin{cases} \mathbb{1}_{(s,t]} & \omega\in F \\ 0 & \text{otherwise} \end{cases}Giving us ∫1(s,t]×F dM=1F(Mt−Ms)\int\limits \mathbb{1}_{(s,t]\times F} \, dM =\mathbb{1}_{F}(M_{t}-M_{s})

Itô Isometry (1)

Let now (Mt)t≥0(M_{t})_{t\ge 0} be a right continuous L2L^{2}-martingale. We denote μM\mu_{M} as the Doléans measure on (R+×Ω,P)(\mathbb{R}^{+}\times\Omega,\mathscr{P}) associated with MM. where P\mathscr{P} is the predictable σ-algebra generated by R\mathcal{R}. Now let F∈FsF\in\mathcal{F}_{s} E[(∫1(s,t]×F dM)2]=E[1F(Mt−Ms)2]=E[1F(Mt2−Ms2)]⏟μM((s,t]×F)E\left[ \left( \int\limits \mathbb{1}_{(s,t]\times F} \, dM \right)^{2} \right]=E[\mathbb{1}_{F}(M_{t}-M_{s})^{2}]=\underbrace{ E[\mathbb{1}_{F}(M_{t}^{2}-M_{s}^{2})] }_{ \mu_{M}({(s,t]\times F}) }which is our first version of the isometry. More formally: ∀0≤s<t,∀F∈Fs\forall 0\le s<t, \forall F\in\mathcal{F}_{s} E[(∫1(s,t]×F dM⏟Itoˆ Stochastic Integral)2]=μM((s,t]×F)=∫R+×Ω1(s,t]×F dμM⏟Lebesgue IntegralE\left[ \left( \smash[b]{\underbrace{ \int\limits \mathbb{1}_{(s,t]\times F} \, dM }_{ \mathclap{\text{Itô Stochastic Integral}} }}\right)^{2} \right]=\mu_{M}({(s,t]\times F}) =\underbrace{ \int\limits _{\mathbb{R}^{+}\times\Omega}\mathbb{1}_{(s,t]\times F} \, d\mu_{M} }_{ \text{Lebesgue Integral} }Which we can think of as a bridge from our Itô stochastic integral to the Lebesgue integral or Lebesgue-Stieltjes integral.

Remark

For 0≤s<t,F∈Fs0\le s<t,F\in\mathcal{F}_{s} E[(∫1(s,t]×F dM)2]=E[1F(Mt2−Ms2)]≥0E\left[ \left( \int\limits \mathbb{1}_{(s,t]\times F} \, dM \right)^{2} \right]=E[\mathbb{1}_{F}(M_{t}^{2}-M_{s}^{2})]\ge 0and for F∈F0F\in\mathcal{F_{0}} ∫1{0}×F dM=0μM({0}×F)=0\int\limits \mathbb{1}_{\{ 0 \}\times F} \, dM =0\quad\mu_{M}(\{ 0 \}\times F)=0

Itô Isometry (2)

We then introduce some sets/σ-algebras:

Proposition (Itô Isometry v2)

Let M=(Mt)t≥0M=(M_{t})_{t\ge 0} be a right continuous L2L^{2}-martingale. We have that the Itô Isometry holds ∀X∈E\forall X\in\mathcal{E} where E[(∫X dM)2]=∫R+×ΩX2 dμME\left[ \left( \int\limits X \, dM \right)^{2} \right]=\int\limits _{\mathbb{R}^{+}\times\Omega}X^{2} \, d\mu_{M}

Remark

This can also be written as ∥∫X dM∥L2(Ω,F,P)=∥X∥L2(R+×Ω,P,μm)\left\lVert \int\limits X \, dM \right\rVert _{L^{2}(\Omega,\mathcal{F},P)}=\lVert X \rVert _{L^{2}(\mathbb{R}^{+}\times\Omega,\mathscr{P},\mu_{m})}

Itô Isometry (3)

Now we extend the previous isometry by proving

Proposition (Density of E\mathcal{E})

E\mathcal{E}, simple predictable processes are dense in L2(R+×Ω,P,μM)L^{2}(\mathbb{R}^{+}\times\Omega,\mathscr{P},\mu_{M}).

This allows us to get to our final destination.

Proposition (Itô Isometry v3)

Let M=(Mt)t≥0M=(M_{t})_{t\ge 0} be a right continuous L2L^{2}-martingale. We have that the Itô isometry holds ∀X∈L2(R+×Ω,P,μM)\forall X\in L^{2}(\mathbb{R}^{+}\times\Omega,\mathscr{P},\mu_{M}) where E[(∫X dM)2]=∫R+×ΩX2 dμME\left[ \left( \int\limits X \, dM \right)^{2} \right]=\int\limits _{\mathbb{R}^{+}\times\Omega}X^{2} \, d\mu_{M}or ∥∫X dM∥L2(Ω,F,P)=∥X∥L2(R+×Ω,P,μm)\left\lVert \int\limits X \, dM \right\rVert _{L^{2}(\Omega,\mathcal{F},P)}=\lVert X \rVert _{L^{2}(\mathbb{R}^{+}\times\Omega,\mathscr{P},\mu_{m})}

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