We first tried to use the LS integral to do this. We first noted that the Lebesgue-Stieltjes measure, μg only worked with gincreasing and that μg was the difference between two increasing functions.
We then saw that for any g=g1−g2 where both g1,g2 are increasing that g then must have finite variation on R+.
To summarize, if we wished to use the LS integral to define ∫YdX we needed X to be a continuousmartingale with finite variaiton but this form meant that X was constant which is pretty useless!
We then thought, ok how about RS integrals? i.e. ∀ω∈Ω∣π∣→0limi=0∑N−1Yti(ω)(Xti+1(ω)−Xti(ω))where π=(t0,…,tN) is a subdivision of [0,1] (for simplicity). We then defined the following: Let g:[0,1]→R be continuous. Define Sπ∈C0([0,1]:R) to be Sπ(f)=i=0∑N−1f(ti)(g(ti+1)−g(ti))Assume lim∣π∣→0Sπ(f) exists ∀f∈C0([0,1]:R). We then applied the principle of uniform boundedness to find that g also needs to have finite variation on [0,1] in order for this to be defined i.e. ∥Sπ∥op=∥f∥∞≤1sup∣Sπ(f)∣=V(g;π)and by the theorem we found that n∈Nsup∥Sπ∥op=n∈NsupV(g;π)<∞ Then considering the standard Brownian motion(Bt)t≥0 we computed 0∫tBsdBs=21(Bt2−t)in probability by applying the framework of the RS integral.
Motivation Trying Again!
Let now (Mt)t≥0 be a right continuousL2-martingale and (Xt)t≥0 be a stochastic process on (Ω,F,P). Our goal is to make sense of ∫XdMin a way that it agrees with the LS pathwise integrals whenever they’re defined.
Itô Isometry (0)
Now, we take g increasing and right continuous meaning we can redefine the Lebesgue-Stieltjes measureμg strictly on intervals of the type (a,b] i.e. since g right continuous ⟹g(b+)=g(b) and g(a+)=g(a) Hence μg((a,b])=g(b)−g(a) Hence for 0≤s<t we define ∫1(s,t]×ΩdM=Mt−MsLetting F⊂Ω we then consider 1(s,t]×F{1(s,t]0ω∈FotherwiseGiving us ∫1(s,t]×FdM=1F(Mt−Ms)
P, predictable σ-algebra We then define E to be the set of set of simple predictable processes where any X∈E can be represented like so: X=i=1∑nai1(si,ti]×Fi+k=1∑ndk1{0}×F0k(★)where 0≤si<ti,Fi∈Fsi,∀i=1,…,n and F0k∈F0,∀k=1,…,n. We then use this to define the new isometry:
Let M=(Mt)t≥0 be a right continuousL2-martingale. We have that the Itô isometry holds ∀X∈L2(R+×Ω,P,μM) where E[(∫XdM)2]=R+×Ω∫X2dμMor ∫XdML2(Ω,F,P)=∥X∥L2(R+×Ω,P,μm)